This is a discussion on Thevenins Theorem within the Off Topic forums, part of the Entertainment category; Calculate the value and direction of the current flowing through the R4 Resistor, Using Thevenins Equivalent...
Page: 1
Is this supposed to be physics? I just started mechanics at school so dunno :P
Its electrical engineering, ive done the actual calculation just want to see if anyone else does the same as what i do =]
fuck you I feel so stupid now and I'm a junior in a private high school in all honors classes h34r:Its electrical engineering, ive done the actual calculation just want to see if anyone else does the same as what i do =][/b]
im doing this in tech for gcse but i dont think this will come up
you doing B.A or Ph.D.?
( im doing B.A in math atm , failed probabilty and statistics course tho :P )
i thought awhile about going to school for this same stuff but at the time there was alot of unemployed looking for same jobs that already went through school figured its a waiste
Its electrical engineering, ive done the actual calculation just want to see if anyone else does the same as what i do =][/b]
a.q I used to be able to do this a few years ago
gimme a problem with auto-cadd or something like that :P
From the left. First loop has a current of I1, middle loop has current of I2, third loop has current of I3
4+ 15(I1-I2) + 5 I1 = 0
-6 + 6 I3 + 8(I3 - I2) = 0
8(I2-I3) + 10 I2 + 15(I2-I1) = 0
3 equations 3 unknowns. Find all three Is.
I think the picture is pointing resistor 4 as the 8Ohm resistor which lies in between loop 2 and 3.
So the current through that resistor will be I2-I3.
Don't know about the states but I dont think its that different. EE's job opportunity in the future in Canada is one of the highest. Starting average salary is about 60k which is decent for coming out first year. After becoming license, the salary is usually around 100-120k which I can settle for. Its one of the hardest Engineering disciplines. Definitely not a waste of time.
:blink:From the left. First loop has a current of I1, middle loop has current of I2, third loop has current of I3
4+ 15(I1-I2) + 5 I1 = 0
-6 + 6 I3 + 8(I3 - I2) = 0
8(I2-I3) + 10 I2 + 15(I2-I1) = 0
3 equations 3 unknowns. Find all three Is.
I think the picture is pointing resistor 4 as the 8Ohm resistor which lies in between loop 2 and 3.
So the current through that resistor will be I2-I3.
Don't know about the states but I dont think its that different. EE's job opportunity in the future in Canada is one of the highest. Starting average salary is about 60k which is decent for coming out first year. After becoming license, the salary is usually around 100-120k which I can settle for. Its one of the hardest Engineering disciplines. Definitely not a waste of time.[/b]
wow..your smart. :mellow:
u lost me when i read electricity.
zuhah i am freshman in private skool in algebra 2. so i not use that shit till college
I hate electrics might be a problem doing Computer engineering :/
Bookmarks